i have to start all over againWhat's your AIM "uptime" record?
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Hmm ok I'm having a weird program. After I've been signed onto AIM for exactly 24 hours on the button it signs me off. I can sign right back on or even autoreconnect no problem but I don't understand why it boots me. I have DSL and my DSL has been up since I got it, that isn't the problem. Very weird. 
t0ne wrote:that is very weird i have not the first clue are you sure your dsl modem doesnt reset itself every 24 hours or something
As far as I know the problem is only with AIM itself. Because I have been download, web browsing, etc when it hit 24hrs and AIM was the only thing affected. My LAN shows that it has been up without any problems. It is not at 24hrs online, it is at 24hrs signed on that the problem occurs. I don't know, very odd.
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Master Jedi
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what??? if you take the integral of a increasingly smaller number (as X^2 tends to infinity, the inverse tends towards 0, and like the limit squeeze theorem, your multiplying a big number by 0, which translates to being online 0 seconds!)
correct me if i'm wrong... but how exactly do you integrate from negative infinity? you need to define a constant to start integrating from...
correct me if i'm wrong... but how exactly do you integrate from negative infinity? you need to define a constant to start integrating from...
dialups can stay connected that long.. maybe not a AOL version.. but many other dialups can.. even aolnet connect kept me online for 8 days.. just depends on how much you stress it and yer computer is fast enuf to handle the whopping 56k data.. thats alli would REALLY like to see some proof on that........ a dialup connection wouldnt stay connected that long.
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Master Jedi
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Your calculus is a little rusty. The integral is infinity. It's the sum of 1/x² for all real x. Also, many functions can be integrated from mius infinity to infinity. For example: [sin(x)]/(x²+1), which is pi*i*sinh(1), but since it has no real part, the integral is 0. The immaginary part can be important in higher math. Finally...0 * infinity is not zero. It is called indeterminate. You should know that if you've taken even basic calculus.dyingeyes wrote:what??? if you take the integral of a increasingly smaller number (as X^2 tends to infinity, the inverse tends towards 0, and like the limit squeeze theorem, your multiplying a big number by 0, which translates to being online 0 seconds!)
correct me if i'm wrong... but how exactly do you integrate from negative infinity? you need to define a constant to start integrating from...
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Master Jedi
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My online time is far greater than yours. It's yours raised to the (infinity + 1)th power. And I'm sure you know that not all infinities are created equal, and mine beats yoursjester22c wrote:idejsecrofkrad wrote:I've been online longer than any of you guys can immagine:
Did you see mine above? I win
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hoozdapimp
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obviously you haven't taken enough calculusdyingeyes wrote:what??? if you take the integral of a increasingly smaller number (as X^2 tends to infinity, the inverse tends towards 0, and like the limit squeeze theorem, your multiplying a big number by 0, which translates to being online 0 seconds!)
correct me if i'm wrong... but how exactly do you integrate from negative infinity? you need to define a constant to start integrating from...
...you can definitely integrate from -infinite to +infinite, although your first statement was correct...1/x^2 is retarted...that does go to 0...
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